Math, asked by vishalbhattacharjee, 4 months ago

2x-7y+8z=0
7x-8y-5z=0
3x+5y+7z=52
Using cross-multiplication method​

Answers

Answered by Anonymous
0

The given system of equations is  

2x+7y−5=0  

−3x+8y=−11    

For the cross multiplication method, we write the coefficients as  

Hence, we get  

(7)(11)−(8)(−5)

x

​  

=  

(−5)(−3)−(2)(11)

y

​  

=  

(2)(8)−(−3)(7)

1

​  

 

That is,  

117

x

​  

=  

−7

y

​  

=  

37

1

​  

. i.e., x=  

37

117

​  

,y=−  

37

7

​  

.

Hence, the solution is (  

37

117

​  

,−  

37

7

​  

).

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