2x-7y+8z=0
7x-8y-5z=0
3x+5y+7z=52
Using cross-multiplication method
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The given system of equations is
2x+7y−5=0
−3x+8y=−11
For the cross multiplication method, we write the coefficients as
Hence, we get
(7)(11)−(8)(−5)
x
=
(−5)(−3)−(2)(11)
y
=
(2)(8)−(−3)(7)
1
That is,
117
x
=
−7
y
=
37
1
. i.e., x=
37
117
,y=−
37
7
.
Hence, the solution is (
37
117
,−
37
7
).
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