Math, asked by davejeet6972, 1 year ago

2x^8.7 =100 how to solve it


Anonymous: Hey! which class ??
Anonymous: you need to use log

Answers

Answered by VijayaLaxmiMehra1
0
Answer:-

 =  > x =  \sqrt[87]{50 {}^{10} }

Step by step explanation


2x {}^{8.7}  = 100 \\  \\
Divide both sides of the equation by 2

 =  > x {}^{8.7}  = 50 \\  \\
using \:  \: a {}^{ \frac{m}{n} }  = \sqrt[n]{a {}^{m} } , \: transform \:  \: the  \\ \:  \: expression

 =  >  \sqrt[10]{x {}^{87} }  = 50
Raise both sides of the equation to the power of 10

 =  > x {}^{87}  = 50 {}^{10}
Take the root of both sides of the equation

 =  > x =  \sqrt[87]{50 {}^{10} }

Hope it helps!
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