Question

Зу - 2x = 9,
2х + 5y = 15​

Answer 1

3y - 2x = 9 =≥ Equation 1.

2x + 5y = 15 =≥ Equation 2.

Solving the value of y in Equation 1,

3y - 2x = 9

3y = 9 + 2x

$y = \dfrac{9 + 2x}{3}$

substituting the value in equation 2,

2x + 5y = 15

$2x + 5( \dfrac{9 + 2x}{3}) = 15$

$2x + \dfrac{45 + 10x}{3} = 15$

LCM = 3 in LHS (Left Hand Side)

$\dfrac{6x + 45 + 10x}{3} = 15$

$\dfrac{16x + 45}{3} = 15$

by cross multiplication,

$16x + 45 = 15 \times 3$

$16x + 45 = 45$

Transposing 45 to the RHS (Right Hand Side)

$16x = 45 - 45$

$16x = 0$

$x = \dfrac{0}{16}$

$x = 0$

Therefore,

$y = \dfrac{9 + 2x}{3}$

$y = \dfrac{9 + 2(0)}{3}$

$y = \dfrac{9}{3}$

by reducing to the lowest terms,

$y = 3$

Verification :

substituting the values of x and y in the Equations

Equation 1 :

3y - 2x = 9

3(3) - 2(0) = 9

9 - 0 = 9

LHS = RHS = 9

Equation 2 :

2x + 5y = 15

2(0) + 5(3) = 15

0 + 15 = 15

LHS = RHS

Hence verified.

x = 0

y = 3

Answer 2

Answer:

0,3

Step-by-step explanation: