Question

= √2x+ 9 - √x- 4 - 3=0​

Answer 1

$\huge {\boxed {\boxed{\red {Solution}}}}$

$\sqrt{2x} + 9 - \sqrt{x} - 4 - 3 = 0$

$\sqrt{2x} - \sqrt{x} + 9 - 7 = 0$

$\sqrt{x} (2 - 1) + 2 = 0$

$\sqrt{x} (1) = - 2$

$\sqrt{x} = \dfrac{ - 2}{1}$

$\sqrt{x} = - 2$

$x = ({ - 2})^{2}$

$\huge{\boxed{\boxed{\mathscr{\red{x=4}}}}}$