Question

(2x+b)^2_a^2=0 solve this equeation
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Answer 1

Step-by-step explanation:

(2x+b)²-a²=0

(2x+b+a)(2x+b-a)=0

2x= -(a+b) or 2x=a-b

x= -(a+b)/2 or x=(a-b)/2

Answer 2

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(2x + b)² - a² = 0

Bu using the formula, a²-b² = (a-b) (a+b),

(2x + b - a) (2x + b + a) = 0

2x + b - a = 0 or 2x + b + a = 0 [Zero Product Rule]

2x = a - b or 2x = -a - b

x = (a-b)/2 or (-a-b)/2