Question

2x + kx +3=0

) kx (x-2)+6=0

Find the values of k for each of the following quadratic equations, so that they have equal roots:


$2 {x}^{2} + kx + 3 = 0$




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Answer 1

Answer:

see the pic......

Step-by-step explanation:

hope this will help you

Answer 2

Here Is Your Answer Mate.....;

2x^2 + kx + 3 = 0

Comparing the given equation with ax^2 + bx + c = 0, we get,

a = 2, b = k and c = 3

As we know, Discriminant = b^2 – 4ac

= (k)^2 – 4(2) (3)

= k^2 – 24

For equal roots, we know,

Discriminant = 0

k^2 – 24 = 0

k^2 = 24

k = ±√24 = ±2√6

Hope it's Helpful.....:)