2x-ky+3=0,4x+6y-5=0 are parallel find k
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Answered by
5
2x-ky+3=0
4x+6y-5=0
If the lines are parallel
a1\b1=a2\b2
2\4=-k\6
k= -24\2
k=-12
4x+6y-5=0
If the lines are parallel
a1\b1=a2\b2
2\4=-k\6
k= -24\2
k=-12
Answered by
1
from no Solution
a1/a2=b1/b2
2/4=-k/6
so -k =24/2
-k=12
a1/a2=b1/b2
2/4=-k/6
so -k =24/2
-k=12
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