2x +ky =5
4x+8y=10
find the k, if the equation have infinite many solutions
Answers
Answered by
1
Answer:
Step-by-step explanation:
Given equations are 2x+3y−5=0 and 4x+ky−10=0
Then 2x+3y−5=0⇒2x+3y=5
4x+ky−10⇒4x+ky=10
∴
4
2
=
k
3
=
10
5
.... [Since, they have an infinite number of solutions]
⇒
2
1
=
k
3
=
2
1
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