Question

2x+ky=6,4x+6y=0•find the value of k for unique solution​

Answer 1

A/Q
It has a unique solution.. so,
$\frac{a1}{a2} \: \: \: is \: not \: equal \: to \: \frac{b1}{b2}$

Answer 2

8x+4ky=24. .....×4

8x+12y=0. ........×2

......................

0-8ky=24

k=-3y

or

k=-3

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