Question

2x + ky -9 = 0 and kx + 3y - 13 =0 has unique solution

answer fast i will mark you as brainlist​

Answer 1

Answer:

K ≠ (-4)

Any value of k can be there for unique solution for the given equations except (-4)

So,

One value of k can be 6

SOLUTION :-

\begin{gathered}2x + 3y - 5 = 0 \\ \\ kx - 6y - 8 = 0 \\ \\ for \: unique \: solution \: \\ \\ \frac{a1}{a2}\: not \: equal \: to \: \frac{b1}{b2} \\ \\ so \\ \\ \frac{2}{k} \: not \: equal \: to \: \frac{3}{( - 6)} \\ \\ \frac{2}{k} not \: equal \: to \: \frac{( - 1)}{2} \\ \\ so \\ \\k \: not \: equal \: to \: ( - 4)\end{gathered}

2x+3y−5=0

kx−6y−8=0

foruniquesolution

a2

a1

notequalto

b2

b1

so

k

2

notequalto

(−6)

3

k

2

notequalto

2

(−1)

so

knotequalto(−4)

Thanks!