Question

2x powre2 +11x+42 Find x

Answer 1

$2 {x}^{2} + 11x + 42 = 0$
$x = \frac{ - 11 + - \sqrt[2]{121 - 4 \times 2 \times 42} }{2 \times 2}$
$x = \frac{ - 11 + - \sqrt{121 - 336} }{4}$
$x = \frac{ - 11 + - \sqrt{ - 215} }{4}$
$x = \frac{ - 11 + \sqrt{ - 215} }{4}$

$or$
$x = \frac{ - 11 - \sqrt{ - 215} }{ 4}$

$in \: question \: you \: have \: not \: mentioned \: what \: is \: equal \: to \: 2 {x}^{2} + 11x + 42 \: thats \: why \: i \: have \: assumed \: 0$

Answer 2

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