Question

(2x)square/(1-x)(3-3x)cube=4/27.find x.

Answer 1

$( \frac{ {2x})^{2}}{(1 - x) ({3 - 3x)}^{3} } = \frac{4}{27}$

on simplification

${x}^{2} - 3x - 1 = 0$

i don't know what to do after this