Question

2x square + 2x-612=0
In factorization method

Answer 1

$2 {x}^{2} + 2x - 612 = 0$

Dividing both sides by 2,

${x}^{2} + x - 306 = 0$

${x}^{2} + 18x - 17x - 306 = 0$

$x(x + 18) - 17(x + 18) = 0$

$(x + 18)(x - 17) = 0$

$x + 18 = 0$

OR

$x - 17 = 0$

$x = - 18$

OR

$x = 17$