Question

2x square - 80x+800 =0​

Answer 1

$2 {x}^{2} - 80x + 800$

Here a=2

b=-80

c=800

D= b^2-4ac

D= 6400-6400

D= 0

Now,

X= -b/2a

X= 80/4

X= 20.

Hope it helps.

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Answer 2

2 Xsqu - 80x +800 =0

2(xsqu - 40x +400) =0

x sque -40x+400 =0

xsque -20x -20x +400=0

x(x-20) -20(x -20) =0

(x-20) (x-20) = 0

therefore , x=0 +20

x = 20

Hence , proved