Question

2x square-x+1 by 8=0 in quadratic equation​

Answer 1

Answer:

i am in 9 class i dont know cos theta agram bagram

Answer 2

Step-by-step explanation:

$\frac{2 {x}^{2} - x + 1}{8} = 0 \\ \\ 2 {x}^{2} - x + 1 = 0 \\ \\ take \\ \\ \: d = {b}^{2} - 4ac \\ \\ d = {1}^{2} - 4 \times 2 \times 1 \\ \\ d = 1 - 8 \\ \\ d = - 7 < 0 \\ \\ hence \: the \: equation \: has \: imaginary \: roots$