2x square +. x. -. 6. is equal to zero
"solve by completing square"
Answers
Answered by
0
The answer is
(√2x+3upon√2-√3upon2)(√2x+3upon√2+√3upon2)
(√2x+3upon√2-√3upon2)(√2x+3upon√2+√3upon2)
Answered by
0
2x^2+x-6 = 0
x^2+x/2-3 = 0
x^2+x/2 = 3
x^2+2.x.1/4 = 3
Adding (1/4)square on both the sides
x^2+2.x.1/4+(1/4)^2 = 3+(1/4)^2
(x+1/4)^2 = 3+1/16
(x+1/4)^2 = 49/16
x+1/4 = + or - root of 49/16
x+1/4 = + or - 7/4
x = + or - 7/4 - 1/4
x = 7/4-1/4
= 6/4
= 3/2
and
x = -7/4-1/4
= -8/4
= -2
The roots are 3/2 and -2
Hope this helps you
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Anonymous:
plz mark me as the brainliest
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