2x square + y square + 8z square - 2 root 2 xy + 4 root 2 yz - 8xz
Answers
Answered by
0
Answer:
since -2√2xy is minus and -8xz is minus and x is common so it will be (-√2x)^2 +y^2 + (2√2z)^2.....
=(-√2x +y+ 2√2x)^2 Ans
Similar questions