Question

2x square + y square + 8z square -2 root 2 xy +4 root 2 yz -8xz

Answer 1

here is your answer dear friend

Answer 2

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Here is your answer.
$2 {x}^{2} + {y}^{2} + 8z {}^{2} - 2 \sqrt{2} xy + 4 \sqrt{2} yz - 8xz \\ \\ = ( - \sqrt{2} x) {}^{2} + {y}^{2} + (2 \sqrt{2} z) {}^{2} + 2 \times ( - \sqrt{2} )x \times y + 2 \times y \times 2 \sqrt{2} z + 2 \times 2 \sqrt{2} z \times ( - \sqrt{2}x ) \\ \\ = ( - \sqrt{2} x + y + 2 \sqrt{2} z) {}^{2}$
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