Math, asked by sarthakthakur007, 10 months ago

2x2x^{2} +11x+14
solve this quadratic equation
if the equation is wrong let me know

Answers

Answered by Anonymous
3

Step-by-step explanation:

The question is not wrong but bit confusing.

2 \times 2 {x}^{2}  + 11x + 14 \\  = 4 {x}^{2}  + 11x + 14 \\

is the quadratic equation.

D=b²-4ac

= (11)²-4(4)(14)

= 121-224

= -103

so D is in negative.

So no roots are possible

Answered by Anonymous
3

Answer:

4{x}^2+11x+14

so this is a quadratic equation.

to check the real roots .

Formula is = D = b^{2}-4ac

 4{x}^2 +11x +14

putting the value in the formula .we get,

a =4

b =11

c =14

so,

 11^{2} -4(4×14)

 121  - 4×56

    121 - 224

 -103

D is a negative number and it's value is less than 1

here is no real roots.

but your equation is quadratic.

_________________badboy________________

Similar questions