Question

2x
${2x}^{2} - 2x + \frac{1}{2} = 0$
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Answer 1

Here's your answer

$2 {x}^{2} - 2x + \frac{1}{2} = 0 \\ \\ \frac{4 {x}^{2} - 4x + 1}{2} = 0 \\ \\ \\ 4 {x}^{2} - 4x + 1 = 2 \\ \\ 4 {x}^{2} - 4x - 1 = 0$

$4 {x}^{2} - 2x - 2x - 1 = 0 \\ \\ 2x(2x - 1) - 1(2x - 1) \\ \\ (2x - 1)(2x - 1) \\ \\ x = \frac{1}{2}$

✔The given equation have real and equal roots....