Question

2x
$2x {}^{2} + 7x + 6x$
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Answer 1

$2 {x}^{2} + 7x + 6 \\ \\ \\ = > 2 {x}^{2} + 4x + 3x + 6 = 0 \\ = \geqslant 2x(x + 2) + 3(x + 2) = 0 \\ \\ = \geqslant( 2x + 3)(x + 2) = 0 \\ \\ \\ = > x = - 2 \\ = > x = \frac{ - 3}{2}$

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Answer 2

-(2x^2 - 7x + 6)

= -(2x^2 - 4x -3x + 6)

= -{ 2(x - 2) -3(x - 6)}

= -(x - 2) (x - 3)

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