Math, asked by sabarivaikuntam, 6 hours ago

2x2x^{2} +x-3=0\\

Answers

Answered by Anonymous
28

\Large\sf\underline{Given:}\\

2x \bf\color{black}{2x^{2}+x-3=0}\\

\large\sf\underline{To\:find:}\\

\sf\color{grey}{The\:value\:of\:x.}\\

\large\sf\underline{Solution:}\\

2x \bf\color{black}{2x^{2}+x-3=0}\\

\bf\color{black}{●\:\: Multiplying\:by\: 2,\: So \:we \:get}\\

\bf{4x^{2}+2x-6=0}

\large\sf\underline{Using\: middle\:term\: breaking\: method:}

In this method we are going to split the middle term such a way that when we multiply it should be equal to 4x6 i.e. 24 and when we subtract it should be equal to 2.

\sf{4x^{2}+(6-4)x -6=0}\\\\\sf{4x^{2}+6x-4x-6=0}\\\\\sf{2x(2x+3)\:-2(2x-3)=0}\\\\\sf{(2x+3)\:(2x-2)=0}\\

\sf\color{grey}{Now\:,}\\

\sf{(2x+3)=0\:,\:(2x-2)=0}\\\sf{2x=-3\:\:\:\:,2x=2}

\tt\color{lightpink}{Hence,}

\tt\Large\color{teal}{x =  \frac{ - 3}{2} \:and \:1}

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