Question

2x* -x+ 1/8=0
Find the root of following Quadratic equation by
Factorisation

Answer 1

$\textbf{Given:}$

$\mathsf{Equation\;is\;2x^2-x+\dfrac{1}{8}=0}$

$\textbf{To find:}$

$\textsf{Roots of the given quadratic equation}$

$\textbf{Solution:}$

$\textbf{Factorisation:}$

$\boxed{\begin{minipage}{8cm} \\\textsf{The method of writing a polynomial into product}\\\\\textsf{of its factors is called Facorisation.}\\ \end{minipage}}$

$\mathsf{Consider,}$

$\mathsf{2x^2-x+\dfrac{1}{8}=0}$

$\mathsf{2x^2-\dfrac{1}{2}x-\dfrac{1}{2}x+\dfrac{1}{8}=0}$

$\mathsf{2x\left(x-\dfrac{1}{4}\right)-\dfrac{1}{2}\left(x-\dfrac{1}{4}\right)=0}$

$\mathsf{\left(2x-\dfrac{1}{2}\right)\left(x-\dfrac{1}{4}\right)=0}$

$\implies\mathsf{2x-\dfrac{1}{2}=0\;\;or\;\;x-\dfrac{1}{4}=0}$

$\implies\mathsf{2x=\dfrac{1}{2}\;\;or\;\;x=\dfrac{1}{4}}$

$\implies\mathsf{x=\dfrac{1}{4}\;\;or\;\;x=\dfrac{1}{4}}$

$\implies\boxed{\mathsf{x=\dfrac{1}{4},\dfrac{1}{4}}}$

$\textbf{Answer:}$

$\mathsf{Roots\;are\;\dfrac{1}{4},\;\dfrac{1}{4}}$

$\textbf{Find more:}$

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