Question

2x/x+3=2x-1/x.solve for x?

Answer 1

i hope it will help u....

Answer 2

Dear Student,

By applying the basic principles of fractional cross multiplication that is,

$\bf{\dfrac{a}{b} = \dfrac{c}{d}; \: then, \: a \times d = b \times c}$

$\bf{2xx = (x + 3) \: (2x - 1)}$

$\bf{2x^2 = x \times 2x + x (- 1) + 3 \times 2x + 3 (- 1)}$

$\bf{2x^2 = 2x^2 - 1 \times x + 3 \times 2x - 3 \times 1}$

$\bf{2x^2 = 2x^2 - x + 6x - 3}$

$\bf{2x^2 = 2x^2 + 5x - 3}$

Subtracting the term of "2x^2 + 5x" from both the given sides;

$\bf{2x^2 - (2x^2 + 5x) = 2x^2 + 5x - 3 - (2x^2 + 5x)}$

$\bf{- 5x = -3}$

Divide both the given sides by the valued number of "- 5" that is,

$\bf{\dfrac{- 5x}{- 5} = \dfrac{- 3}{- 5}}$

$\boxed{\bf{\underline{\therefore \quad x = \dfrac{3}{5}}}}$

Which is the required answer for these types of given queries.

Hope it helps you and clears your doubts for obtaining the values of variable "x" by simplifying fractions !!!!