Question

(2x/x+3)-(4/x-3)=(-6/x+3)

Answer 1

hi friend

(2x/x+3)-(4/x-3)=(-6/x+3)

(2x+3x/x) -(4 - 3x /x) =(-6+3x/x)
2x+3x/x - 4+3x/x=(-6+3x/x)
5x -4+3x/x=-6+3x/x
8x -4/x=-6+3x/x
x(8x-4)=x(-6+3x)

$8 {x}^{2} - 4x = - 6x + 3 {x}^{2} \\ 8 {x}^{2} - 3 {x}^{2} - 4x + 6x = 0 \\ 5 {x}^{2} + 2x = 0 \\ x(5x + 2) = 0 \\ 5x = - 2 \\ x = - 2 \div 5$
I hope it will help you

Answer 2

Answer:

here is ur ans......

(2x/x+3)-(4/x-3)=(-6/x+3)

(2x+3x/x) -(4 - 3x /x) =(-6+3x/x)

2x+3x/x - 4+3x/x=(-6+3x/x)

5x -4+3x/x=-6+3x/x

8x -4/x=-6+3x/x

x(8x-4)=x(-6+3x)

8x2−4x=−6x+3x28x2−3x2−4x+6x=05x2+2x=0x(5x+2)=05x=−2x=−2÷5\begin{lgathered}8 {x}^{2} - 4x = - 6x + 3 {x}^{2} \\ 8 {x}^{2} - 3 {x}^{2} - 4x + 6x = 0 \\ 5 {x}^{2} + 2x = 0 \\ x(5x + 2) = 0 \\ 5x = - 2 \\ x = - 2 \div 5\end{lgathered}

8x

2

−4x=−6x+3x

2

8x

2

−3x

2

−4x+6x=0

5x

2

+2x=0

x(5x+2)=0

5x=−2

x=−2÷5

hope it helps u lot........