Question

2x+x-4=0
Slove it by general completing sqares method

Answer 1

2x^2+x-4=0

2(2x^2+x-4)=0

4x^2+2x-8=0

(2x)^2+2*2x*1/2+(1/2)^2
-(1/2)^2-8=0

(2x+1/2)^2-1/4-8=0

(2x+1/2)^2=1/4+8

(2x+1/2)^2=33/8

2x+1/2=+_√(33/8)

2x= -1/2+_√(33)/(2√2)

2x=(-√(2)+_√(33)) / (2√2)

x=(-√2+_√33)/4√2

x=(-√2+√33)/(4√2)
and
(-√2-√33)/(4√2)