Question

2x/x-4 + 2x-5/x-3 =25/2​

Answer 1

Answer:

17$x^{2}$ -137x-260 = 0

Step-by-step explanation:

2x/x-4 + 2x-5/x-3 =25/2​

[2x(x-3) + (x-4)(2x-5)] / (x-4)(x-3) = 25/2

(2$x^{2}$ -6x + 2$x^{2}$ -5x -8x + 20) / ($x^{2}$ -3x-4x+12) = 25/2

(4$x^{2}$ -19x + 20) / ($x^{2}$ -7x+12) = 25/2

2(4$x^{2}$ -19x + 20) = 25($x^{2}$ -7x+12)

8$x^{2}$ -38x + 40 = 25$x^{2}$ -175x+300

25$x^{2}$ -175x+300 = 8$x^{2}$ -38x + 40

17$x^{2}$ -137x-260 = 0