Question

2x ( x -7 + 3x square) + 3x ( x square- 3x + 9)

Answer 1

Answer:

Explanation:

First, subtract 3x and 9 from each side of the equation to put the quadratic equation in standard form:

2x2−3x−9=3x+9−3x−9

2x2−3x−9=3x−3x+9−9

2x2−3x−9=0+0

2x2−3x−9=0

Next, factor the quadratic equation:

(2x+3)(x−3)=0

Now, solve each term for 0:

Solution 1)

2x+3=0

2x+3−3=0−3

2x+0=−3

2x=−3

2x2=−32

2x2=−32

x=−32

Solution 2)

x−3=0

Answer 2

Answer:

$2x(3x { }^{2} + x - 7) + 3x(x ^{2} - 3x + 9) \\ \\ = 9x ^3 - 7x ^{2} + 18x - 14$