Question

2x/x²-49partial fractions
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Answer 1

Answer:

Step-by-step explanation:

$\frac{2x}{x^2-49}=\frac{2x}{(x-7)(x+7)}\\\\2x(\frac{1}{x-7}-\frac{1}{x+7})\times\frac{1}{14}\\\\\frac{x}{7(x-7)}-\frac{x}{7(x+7)}$

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