Question

2x+y=0 and 3x-5y=0 find joint equation​

Answer 1

Hey Dude,

Here is your Answer:

The value of both x and y is 0.

Please choose it brainliest answer.

Step by Step Explanation:

2x + y = 0

2x = 0 - y = -y

$y = - 2x$

3x-5y = 0

3x = 0 + 5y = 5y

$y = \frac{3x}{5}$

From equation (I) and (II), we get:

$- 2x = \frac{3x}{5}$

$- 2x - \frac{3x}{5} = 0$

$\frac{ - 10x - 3x}{5} = 0$

$- 13x = 0$

$x = \frac{0}{ - 13}$

$x = \frac{0}{ - 13}$

$x = 0$

Now,by the same process:-

2x + y = 0

2x = 0 - y = -y

$x = \frac{ - y}{2}$

3x-5y = 0

3x = 5y

$x = \frac{5y}{3}$

From equation (I) & (II), we get:

$\frac{ - y}{2} = \frac{5y}{3}$

$\frac{ - 3y - 10y}{6} = 0$

$- 3y - 10y = 0 \times 6 = 0$

$- 13y = 0$

$y = \frac{0}{ - 13}$

$y = 0$

Hope it helps,

Answer 2

Answer:

6$x^{2}$ - 7xy - 5$y^{2}$ = 0

Step-by-step explanation:

The joint equation of line 2x +y = 0 and 3x - 5y = 0 is

(2x + y)(3x - 5y) = 0

6$x^{2}$ - 10xy +3xy - 5$y^{2}$ =0

6$x^{2}$ -7xy - 5$y^{2}$ = 0