Question

2x+y=10, 6x-5y=8
With cross multiplication
Plz help

Answer 1

$x = \frac{29}{8} \: \: y = \frac{11}{4}$

Step-by-step explanation:

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See The Attachment My Friend....

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Answer 2

Answer:

Step-by-step explanation:

x/B1C2−B2C1=y/C1A2−C2A1=1/A1B2−A2B1

Equating one another we find the value of x and y of the given equations.

Solve for ‘x’ and ‘y’:

2x + y =10 , and

6x-5y=8.

Let us solve the given equations using method of cross multiplication:

The coefficients of x are 2 and 6.

The coefficients of y are 1 and -5.

The constant terms are -10 and -8.

On substituting respective values, we get:

$\frac{x}{[1 * (-8))-(-5*(-10)]} =\frac{y}{[(-10*6)-(-8*2)]} = \frac{1}{[(2*(-5))-(6*1)]}$

$\frac{x}{-8-(50)} = \frac{y}{-60-(-16)} = \frac{1}{-10-6}$

$\frac{x}{-58} = \frac{y}{-60+16} =\frac{1}{-16}$

$\frac{x}{-58} =\frac{y}{-44} =\frac{1}{-16}$

Equating x term with constant term,

x/-58 = 1/-16

x/58 = 1/16

x = 1/16 × 58

x = 29/8   ans...

Equating y term with constant term,

y/-44 = 1/-16

y/44 = 1/16

y = 1/16 × 44

y = 11/4   ans...