Question

2x+y-11=0 , x-y-1 = 0
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Answer 1

Answer:

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Answer 2

$\huge\bf\purple{\mathfrak{Given:-}}$

• Solve the following equations by substitution method:-

2x + y - 11 = 0

and

x - y - 1 = 0.

$\large\underline{\mathtt{\bold{Solution-}}}$

Method of Substitution :-

• To solve systems using substitution, the following procedure is followed :-

• Select one equation and solve it for one of its variables.

• In the other equation, plug in or substitute for the variable just solved in previous step.

• Solve the new equation in one variable to get its value.

• Substitute the value found into any equation involving both variables and solve for the other variable.

Let's solve the problem now!!

Now, given linear equations are

2x + y - 11 = 0 -----(1)

and

x - y - 1 = 0 ----(2)

Step :- 1

From, equation (2), get the value of y in terms of x.

y = x - 1 ----(3)

Step :- 2

Now, Substitute the value of 'y' evaluated in Step 1 in equation (1), we get

2x + x - 1 - 11 = 0

3x - 12 = 0

3x = 12

$\therefore \: \: \boxed{ \tt{x \: = \: 4}}$

x=4

Step :- 3

Now, Substitute the value of 'x' evaluated in Step - 2, in equation (3), we get

y = 4 - 1

$\therefore \: \boxed{ \tt{y \: = \: 3}}$

Hence,

x = 4 and y = 3 is the solution of given Pair of Linear Equations.