Math, asked by sanjhvikataria, 1 month ago

2x-y +13 and x+2y+4 lengths of rectangle .
2x+6 and 3y breadth of rectangle
find value of x and y
find the perimeter and area​

Answers

Answered by yadavsaransh06
5

Answer:

Perimeter = -30 & Area = 39

Step-by-step explanation:

If l = 2x-y +13, then b = 2x+6

If l = x+2y+4, then b = 3y

2(2x - y + 13 + 2x + 6) = 2(x + 2y + 4 + 3y)

(2x - y + 13 + 2x + 6) = (x + 2y + 4 + 3y)

4x - y + 19 = x + 5y + 4

3x - 6y = - 15

x - 2y = -5, x = 2y - 5

Now, (2x-y +13)(2x+6) = (x+2y+4)(3y)

(4y - 10 - y + 13)(4y - 10) = (2y - 5 + 2y + 4)(3y)

(3y + 3)(4y- 10) = (4y - 1)(3y)

12y^2 - 30y + 12y - 30 = 12y^2 - 3y

-18y - 30 = -3

-15y = 30

y = -2, x = -9

Perimeter = 2(-9 -4 + 4 + -6) = 2×-15 = -30

Area = (-18 + 2 + 13) (-18 - 5) = -3 × - 23 = 69

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