2x+y=14 and 3x-y=6 by cross multiplication method
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By cross multiplication method
x=(a1b2−a2b1)(b1c2−b2c1) &
y=(a1b2−a2b1)(c1a2−c2a1)
Where a1x+b1y+c1=0 & a2x+b2y+c2=0
are 2 lines
⇒x=2(−2)−(3×3)3(−6)−(−2)(−17)=−13−52=4
y=2(−2)−(3
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