2x-y-18 y I am a rectangle x-2y+9. 2x+6 . 3y .find the value of x and y .find my perimete and area
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Since it is a rectangle opposites sides are equAL
2x - y -18 = 3y
2x - 4y = 18 (equation 1)
2x + 6 = x - 2y + 9
x + 2y = 3 ( equation 2)
Now multiply equation 2 with 2 and substract it from equation (1)
- 8y = 18 -6
y = -3/2
by substituting the value of y in equation 2,
x + 2 (-3/2) = 3
X = 6
Length(L) = 2x - y - 18 = 2*6 + 3/2 - 18 = 12 +1.5 - 18 - 4.5 = 4.5
breadth (B) = 2x + 6 = 2 *6 + 6 = 18
Perimeter = 2 (1 + b ) = 2 (4.5+ 18) = 45
Area = 1 * b = 4.5 * 18 = 81
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