2x+y=19;2x-3y=-3 simultaneous equation
Answers
Answered by
3
Heya... ☺
Using substitution method --
y = 19 -2x
Substituting the value of y in 2nd equation
2x - 3 (19-2x) = -3
2x - 57 + 6x = -3
8x -57 = -3
8x = -3+57
x = 54/8
Therefore ,
y = 19- 2 × 54/8
y = 19-54/4
y = {36-54} ÷ 4
y = -18/4
Using substitution method --
y = 19 -2x
Substituting the value of y in 2nd equation
2x - 3 (19-2x) = -3
2x - 57 + 6x = -3
8x -57 = -3
8x = -3+57
x = 54/8
Therefore ,
y = 19- 2 × 54/8
y = 19-54/4
y = {36-54} ÷ 4
y = -18/4
dramaqueen6:
hii dear
plzz message me
I have no point so I can't
Answered by
0
Answer:
Step-by-step explanation:
2x+y=19 ......... (1)
2x-3y=3 ..........(2)
subtract equations 2 from 1
2x+y=19
- 2x-3y=3
- + - sin got Change of eq 2
= 4y=16
y=16/4=4
y=4
substitute value of y In eq 1
2x+y=19
2x+4=19
2x=19-4=15
x=15/2=7.5
x=7.5 or 15/2
and
y=4
Similar questions