Math, asked by agarwalrakhee2pcd2i5, 1 year ago

(2x-y)^2-14x+7y-18 factorization

Answers

Answered by kshiitijbhogireddy
9

Answer: 4x2 - 4xy - 14x + y2 + 7y - 18

Step-by-step explanation: (2x-y)2-14x+7y-18  

Final result :

 4x2 - 4xy - 14x + y2 + 7y - 18

Step by step solution :

Step  1  :

Trying to factor by pulling out :

1.1      Factoring:  4x2-4xy-14x+y2+7y-18  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -14x+7y  

Group 2:  4x2-4xy  

Group 3:  y2-18  

Pull out from each group separately :

Group 1:   (2x-y) • (-7)

Group 2:   (x-y) • (4x)

Group 3:   (y2-18) • (1)

Looking for common sub-expressions :  

Group 1:   (2x-y) • (-7)

Group 3:   (y2-18) • (1)

Group 2:   (x-y) • (4x)

Bad news !! Factoring by pulling out fails :  

The groups have no common factor and can not be added up to form a multiplication.

Final result :

 4x2 - 4xy - 14x + y2 + 7y - 18

Answered by astha7212
52

(2x-y)^2-7(2x-y)-18

Let 2x-y=a

a^2-7a-18

a^2-9a+2a-18 (splitting the middle term)

a(a-9)+2(a-9)

(a-9)(a+2)

Now putting a= 2x-y

(2x-y-9)(2x-y+2) Ans.

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