(2x+y) ²+2(2x+y)³ find the factorisation
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Answered by
1
(x + 2y)^2 - 4(2x - y)^2 = (x + 2y)^2 - (2^2)(2x - y)^2= (x+2y)^2 - (2(2x-y))^2= (x+2y)^2 - (4x - 2y)^2 = (x + 2y +(4x-2y ))(x+ 2y - (4x - 2y))= (x + 2y + 4x - 2y)(x + 2y - 4x + 2y) =(5x)(-3x+4y)= 5x(4y - 3x) .
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6
Answer:
(2x+y)²(4x+2y+1)
Explanation:
Substitute t=2x+y and check common factor.
There are t² and +2t³. They share t² as common factor.
Therefore, the factorization is t²(2t+1).
By substitution, correct answer is (2x+y)²(4x+2y+1)
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