Math, asked by simranraj0603, 11 months ago

(2x-y)^2 + (3y-z)^2 = 0, Find x:y:z.

Answers

Answered by KailashNath3

2

Answer:

Step-by-step explanation:

4x2+y2-4xy+9y2+z2-6yz=0

4x2+10y2-4xy+z2-6yz=0

(2x)2+10y2+z2-6yz

2x:5y:z=x:y:z

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