(2x-y)²+5(2x-y)-300
Answers
Answered by
2
(2x-y)^2=(4x^2)-(4xy)+(y^2)
5(2x-y)=10x-5y
[(2x-y)^2]+[5(2x-y)]-300
(4x^2)-(4xy)+(y^2)+10x-5y-300
I hope this helps you and please mark me the Brainliast.
Answered by
1
Step-by-step explanation:
- 4x²+10x+y²-5y-4xy-300
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