Math, asked by akshitadhiman123, 11 months ago

(2x-y)²+5(2x-y)-300​

Answers

Answered by santoshtripathy70
2

(2x-y)^2=(4x^2)-(4xy)+(y^2)

5(2x-y)=10x-5y

[(2x-y)^2]+[5(2x-y)]-300

(4x^2)-(4xy)+(y^2)+10x-5y-300

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Answered by sauravbhardwajp22
1

Step-by-step explanation:

  1. 4x²+10x+y²-5y-4xy-300
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