Question

2x+y/3=12, xy=30 then 8x^3+y^3/27=?

Answer 1

It has given that 2x + y/3 = 12, xy = 30

To find : the value of 8x³ + y³/27

solution : here 2x + y/3 = 12

⇒(2x + y/3)³ = 12³

⇒(2x)³ + (y/3)³ + 3(2x)(y/3)(2x + y/3) = 1728

⇒8x³ + y³/27 + 2xy(2x + y/3) = 1728

as 2x + y/3 = 12 and xy = 30

⇒8x³ + y³/27 + 2(30)(12) = 1728

⇒8x³ + y³/27 + 720 = 1728

⇒8x³ + y³/27 = 1728 - 720 = 1008

⇒8x³ + y³/27 = 1008

Therefore the value of 8x³ + y³/27 is 1008.

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$8x {}^{3} - (2x - y) {}^{3}$

answer.

y [ 12 x ^ + y^ -6xy]

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Answer 2

Answer:

 has given that 2x + y/3 = 12, xy = 30

To find : the value of 8x³ + y³/27

solution : here 2x + y/3 = 12

⇒(2x + y/3)³ = 12³

⇒(2x)³ + (y/3)³ + 3(2x)(y/3)(2x + y/3) = 1728

⇒8x³ + y³/27 + 2xy(2x + y/3) = 1728

as 2x + y/3 = 12 and xy = 30

⇒8x³ + y³/27 + 2(30)(12) = 1728

⇒8x³ + y³/27 + 720 = 1728

⇒8x³ + y³/27 = 1728 - 720 = 1008

⇒8x³ + y³/27 = 1008

Therefore the value of 8x³ + y³/27 is 1008.

also read similar questions : factorise. the polynomial

8x {}^{3} - (2x - y) {}^{3}8x3−(2x−y)3

answer.

y [ 12 x ^ + y^ -6xy]

https://brainly.in/question/2935064

factorise each of the following using identities 8x^3-(2x-y)^3