Question

(2x - y)³ - (2x - y)​

Answer 1

Answer:

............................

Answer 2

Answer:

The factors are; (2x -y)(2x - y+1)(2x -y-1)

Step-by-step explanation:

The question is,

(2x - y)^3 - (2x - y)

Therefore, taking 2x - y common, we get,

2x - y(  (2x - y)^2  - 1^2)

Therefore, factorising the bracket using, a^2 + b^2 - (a+b)(a-b) we get,

2x - y ( 2x - y + 1 )( 2x - y - 1)

HOPE THIS HELPS YOU...