Question

(2x-y) ³-(2x-y) Factories it. ​

Answer 1

Answer:

(2x-y)(2x-y+1)(2x-y-1)

Step-by-step explanation:

Taking (2x-y) common, we get

(2x-y) × [ (2x-y)² - 1 ]

=(2x-y) × [ (2x-y)² - 1 ² ]

Polynomial inside the bracket, is of the form, (a²-b²).

Using Identity: a²-b² = (a+b)(a-b), we get,

(2x-y) × [ { (2x-y) + 1 } { (2x-y) - 1 } ]

That is,

(2x-y)(2x-y+1)(2x-y-1) is the factorised form.