Question

(2x-y)^3+(y-3z)^3+(3z-2x)^3 .

Answer 1

Solution :

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We know that ,

If a + b + c = 0 , then

a³ + b³ + c³ = 3abc

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Here ,

a = 2x - y ,

b = y - 3z ,

c = 3z - 2x
Now ,

a + b + c

= 2x - y + y - 3z + 3z - 2x

= 0

Therefore ,

a³ + b³ + c³

= ( 2x-y )³ + ( y - 3z )³ + ( 3z - 2x )³

= 3abc

= 3( 2x - y )( y - 3z )( 3z - 2x )

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Answer 2

Answer:

Step-by-step explanation: