Question

(2x-y+3z)(4x^2+y^2+9z^2+2xy+3yz-6xz)

Answer 1

Here is solution of your question
=(2x+(-y)+z) {(2x)²+y²+(3z)²-(2x)(-y)-(-y)(3z)-(3z)(2x)

It is based on this formula

=a³+b³+c³-3abc

=2x³+(-y)³+3z³-3(2x)(-y)(3z)

=2x³+(-y)³+3z³+18xyz

Answer 2

Step-by-step explanation:

Rewriting

2x+(-y)+3z((2x)^2+(y)^2+(3z)^2+2x*y+y*3z+3z*2x)

this caters to the identity a^3+b^3+c^3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)

(2x)^3+(-y)^3+(3z)^3-3(2x)(-y)(3z)

8x^3-y+27z^3+18xyz