2x-y+3z=9,x+y+z=6,x-y+z=3
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Given
2x−y+3z=9 ………..(1)
x+y+z=6 …………..(2)
x−y+z=2 …………….(3)
using matrix inversion method
AX=B
⎣⎢⎢⎡211−11−1311⎦⎥⎥⎤ ⎣⎢⎢⎡xyz⎦⎥⎥⎤=⎣⎢⎢⎡962⎦⎥⎥⎤
and X=A−1B where A−1=∣A∣adj(A)
Now adjA=⎣⎢⎢⎡20−2−2−1−1−413⎦⎥⎥⎤
A∣=2(1+1)−1(1−1)+3(−1−1)
∣A∣=4−6
∣A∣=−2.
Now A−1=2−1⎣⎢⎢⎡20−2−2−1−1−413⎦⎥⎥⎤
Now X=A−1B
⎣⎢⎢⎡xyz⎦⎥⎥⎤=2−1⎣⎢⎢⎡20−2−2−1−1−413⎦⎥⎥⎤⎣⎢⎢⎡962⎦⎥⎥⎤
⎣⎢⎢⎡xy
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