2x + y - 3z÷y+3x = x/2y
1. If find the value of z when x = 1 and y = 4.
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Answer:
2x+y-3z÷y+3x=x÷2y
2*1+4-3z+3*1=1÷2*4
2+4-3z+3=1÷8
9-3z=1÷8
8(9-3z)=1
72-24z=1
24z=72-1
24z=71
z=71/24
hazainajan:
I think its kinda wrong the question at the reactant side we first divide it also with y+3x u accidentally added
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