Question

2x+ y = – 4
x + y = -1 solve by using elimination method​

Answer 1

$\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}$

$\boxed {x=-3}$

$\boxed {y=2}$

$\boxed {\underline {\mathbb {GIVEN:-}}}$

$2x+ y = -4\\x + y = -1$

$\boxed {\underline {\mathbb {TO\:FIND:-}}}$

value of x and y

$\boxed {\underline {\mathbb {METHOD\:USED:-}}}$

$elimination \: method$

$\boxed {\underline {\mathbb {SOLUTION:-}}}$

Let $2x+y=-4...(1)$

And

$x+y=-1...(2)$

now by using eq2 let’s make eq3

we get-

$x+y=-1$

$x=-1-y$  [ ← by bringing y to RHS]

hence $x=-1-y...(3)$

now by using elimination method put eq3 in eq1  

we get-

$2(-1-y)+y=-4$ [ ←putted value in eq]

$-1 \times 2-y \times 2 + y =-4 \\-2-2y+y=-4\\-2-y=-4$

$-y=-4+2$ [brought -2 to RHS get +2]

$-y=-2$ [ ← when bring – to RHS we get – and – as +]  

$\boxed {y=2}$

as we get y value so let’s put in eq3 to get x value

$x=-1-(2)$ [← putted y value in eq3]

$x=-1-2\\\boxed {x=-3}$

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Answer 2

Answer:

The value of x is -3.

The value of y is 2.

Step-by-step explanation:

Given,

• 2x + y = -4
• x + y = -1

To Find,

• The Value of x and y.

Solution,

2x + y = -4 •••[1]

x + y = -1 •••[2]

Step 1 : Multiply Equation [2] by 2 to make the coefficients of x equal. Then we get the equations:

2x + y = -4 •••[3]

2x + 2y = -2 •••[4]

Step 2 : Subtract Equation [3] from Equation [4] to eliminate y, because the coefficients of y are the same. So, we get:

(2x + 2y) - (2x + y) = -2 - (-4)

2x + 2y - 2x - y = -2 + 4

y = 2

Step 3 : Substitute this value of y in [1], we get:

2x + y = -4 •••[1]

2x + 2 = -4

2x = -4 - 2

x = -6/2

x = -3

Verification,

2x + y = -4 •••[1]

2(-3) + 2 = -4

-6 + 2 = -4

-4 = -4

L.H.S. = R.H.S.

x + y = -1 •••[2]

-3 + 2 = -1

-1 = -1

L.H.S. = R.H.S.

Required Answer,

• The value of x is -3.
• The value of y is 2.