Math, asked by PayalDadhich4612, 9 months ago

2x-y=4: x-y=1 solve it graphically this linear equation

Answers

Answered by amitkumar44481
57

Given :

We have pair of linear equation,

  • 2x - y = 4. and x - y = 1.

Solution :

Let's

 \tt \fbox {2x - y = 4.} \:  \:  \:  \:  \:  - (1) \\   \tt \fbox{ x - y = 1.} \:  \:  \:  \:  \:  - (2)

Taking Equation, (1)

  \tt \dagger \:  \:  \large When \:  x = 2.

 \tt \longmapsto 2x - y = 4.

 \tt \longmapsto 2(2) - y = 4.

 \tt \longmapsto 4 - y = 4.

 \tt \longmapsto y = 0.

\rule{90}1

  \tt \dagger \:  \:  \large When \:  x = 1.

 \tt \longmapsto 2x - y = 4.

 \tt\longmapsto 2(1) - y = 4.

 \tt\longmapsto  - y = 4 - 2.

 \tt \longmapsto y =  - 2.

\rule{90}1

  \tt \dagger \:  \:  \large When \:  x = 0.

 \tt \longmapsto 2x - y = 4.

 \tt\longmapsto 2(0) - y = 4.

 \tt\longmapsto - y = 4.

 \tt\longmapsto y =  - 4.

\begin{array}{| c | c | c | c |} \cline{1-4} x & 2 &  1 & 0 \\ \cline{1-4} y & 0 & -2 & -4 \\ \cline{1-4}\end{array}

\rule{200}3

Taking Equation (2)

 \tt \longmapsto x - y = 1.

  \tt \dagger \:  \:  \large When \:  x = 1.

 \tt \longmapsto 0 - y = 1.

 \tt \longmapsto  - y = 1.

 \tt\longmapsto y =  - 1.

\rule{90}1

  \tt \dagger \:  \:  \large When \:  x = 2.

 \tt\longmapsto x - y = 1.

\tt\longmapsto (2) - y = 1

\tt\longmapsto  - y = 1 - 2

\tt\longmapsto  - y =  - 1

\tt\longmapsto y = 1.

\rule{90}1

  \tt \dagger \:  \:  \large When \:  x = 1.

\tt\longmapsto x - y = 1.

\tt\longmapsto (1) - y = 1

\tt\longmapsto  - y = 0

\tt\longmapsto y = 0.

\begin{array}{| c | c | c | c |} \cline{1-4} x & 1 &  2 & 1 \\ \cline{1-4} y & -1 & 1 & 0 \\ \cline{1-4}\end{array}

\rule{200}3

Note : Graph provide in attachment, where as, red color show Equation (2) and green color show Equation (1).

Attachments:
Answered by billymusinya90
7

Answer:

y=2,x=-1

Step-by-step explanation:

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