2x-y=4 , y-z=6 , x-z=10
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2x−y=4 ..(i)
y−z=6 ..(ii)
x−z=10 ..(iii)
From equation (iii), we get z=x−10
Substituting the value of z in equation (ii), we get
y−(x−10)=6
⇒−x+y=−4 ...(iv)
Adding equations (i) and (iv), we get
x=0
Putting x=0 equation in (i) and (iii) we get
y=−4 and z=−10
Hence, x=0,y=−4,z=−10 is the solution of the given system of equations.
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